Bedienungsanleitung Texas Instruments TI-10

Inhaltszusammenfassung zur Seite Nr. 1

Display Indicators
Indicator Definition
‹
TI-10 is in the Problem Solving tool.

ƒ
TI-10 is in the Place Value feature.
Fix TI-10 is rounding results.
TI-10
M A value other than zero is in memory.
Op1
Calculator and Arithmetic Trainer Stored operation is active.
Problem Solving ( ) is in AUTO (automatic)
Auto ‹
Copyright ª 2001, 2002 Texas Instruments Incorporated
mode.
. P When using W, result will be displayed in
General Information
decimal format.
The TI-10 has two power source

Inhaltszusammenfassung zur Seite Nr. 2

W ‹  [ \ Division Problem Solving Problem Solving lets you practice and test your skills. When you divide a positive whole number by a positive whole number using W, the result is displayed in the form Q To enter Problem Solving, press . r R, where Q is the quotient and R is the remainder. For You can choose either AUTO (automatic) or MAN (manual) example, if you are in the QR setting: 12 ‚ 5 = 2 r 2. mode. If you use the result of QR division in a subsequent AUTO Mode calculation, the TI-10

Inhaltszusammenfassung zur Seite Nr. 3

However, if you enter an answer, it will tell you whether your 2. Remove the screws from the back of the case, using a small answer is less than < or greater than > the correct answer. Phillips screwdriver. Inequalities. Instead of entering an equation, you can test an 3. Carefully separate the front from the back, starting from the inequality using [ or \. You get only one try because bottom of the case. the inequality statement is either true or false. With Caution: Be careful not to damage a

Inhaltszusammenfassung zur Seite Nr. 4

­ T U V W Z ! " # $ ” w (continued) ­­ 6 T21 3 6+21 b ” wwZ 3 6+2= 8 T 2 T 3 Z 7 T 3!!w 6 Z 2+3= 5 6+3= 9 U 7 U 4 Z 6 U 5wwT 4 Z 7N4= 3 6+4= 10 V 2 V 4 Z 2 4= 8 Q W ‡ b ” 3 W 6 W 3 Z 6P 3 = 2 r 0 W 9 W 4 Z 9P4 2 r 1 # ### 2+3= 5 7N4= 3 ÙP ‡"® $$ QR Ù ê 7N4= 3 P 2Q4= 8 ÙP ” ! " !!! 4"" 2 Z 9P 4 = 2 r 1 74N42= 32 ÙP 9 W 4 Z T # # 9P 4 = 2.25 b ” 3 r ‡ T 1 T 1 Z b ” 1+1= 2 3 r 1 T 2 Z 6 r 3 T 2 r 4 Z 1+2= 3 6.3+2.4= 8.7 1 T 3 Z 4 r 2 V 3 r 1 Z 1+3= 4 4.2Q3.1= 13.02 ÙP 1 T 4 Z ‡"®

Inhaltszusammenfassung zur Seite Nr. 5

Š ˜ ™ “ ’ ‘  (continued) X Y Fix Š Š  4000. b ” 3 Fix Š ‘Š ‘ 4100. 3 V 4 T 2 Z 3Q4+2= 14 Fix Š ’Š ’ 4130. X Y 3VX 4 T 2YZ Q 3Q(4+2)= 18 Fix Š “Š “ 4128. ` a Fix Š ˜Š ˜ b ” 4128.4 3 Fix Š ™Š ™ 4 T 2 Z 4+2= 6 4128.41 `` M Š r Š r 4+2= 6 4128.412508 M 1 T 1 Z ‹ 1+1= 2 b ” 3 M aa 1+1= 2 ‹ Auto ‹‹ 8+3=? M || 3 43 ‹ Auto 11 ® 8+3=11 M T 1 Z YES 4+1= 5 ‹ Auto 3+?=8 || ” 3 3 ‹ Auto 5 ® 3+5=8 YES › ‹ Auto b ” 9+7=? 3 3 ‹ Auto 15 ® Op1 › ›T 1 › 9+7>15 +1 NO ‹ Auto 18 ® Op1 1 › 9+7<18 1+1 NO 12 ‹ Auto 1

Inhaltszusammenfassung zur Seite Nr. 6

‹ ‡ ‹ ‡ Œ ™ ˜ “ ’ ‘  b ” b ” 3 3 ‹ Auto ‹‡ " ® 1 2 3 $ ‹ ‹‡ ‹ ‡ " ® 1 2 3 AUTO MAN ê ë ì ‹ Auto ‡ ‹ ‡ 6+400=? 3 3 ‹ Auto 406 ® ‹ƒ Œ 4379 r65 Œ 6+400=406 4379.65 YES 3 ‹ Auto + N Q P ? ‡$$"" ‹ƒ 3 + N Q P ? 4379.65 ® ê3êê.êê ‹ Auto ‹ƒ ‡ 10Q40=? 4379.65 3 3"100 ‹ƒ ‹ Auto 400 ® 5 10Q40=400 4379.65 êêêê.ê5 YES ‹ƒ ‹ Auto ‡$$ ! ® 4379.65 70N40=? ‡ 5"0.01 3 ‹ ‹ Auto ”7653 r49 Œ 20 ® 7653.49 70N40>20 3 NO ‹ƒ  ‹ Auto 30 ® 7653.49 7