Bedienungsanleitung Texas Instruments TI-15

Inhaltszusammenfassung zur Seite Nr. 1

Display Indicators Integer Division £
When you divide a positive whole number by a positive
Indicator Definition
whole number with £, the result is displayed in the form
‹ Calculator is in Problem Solving mode.
Q r R, where Q is the quotient and R is the remainder.
TIN15
ƒ Calculator is in Place Value mode.
If you use the result of integer division in a subsequent
calculation, the TI-15 uses only the quotient; the remainder
Fix Calculator is rounding results.
Calculator and Arithmetic Trainer
i

Inhaltszusammenfassung zur Seite Nr. 2

Stored Operations › œ Problem Solving (continued) Error Conditions Arithmetical error. Op1 and Op2 each can store an operation with a constant When you first enter ‹ and when you press ‡, the Arith Error value, which you can repeat by pressing only one key, as display shows the Scoreboard for a moment before Syntax error. Syn Error many times as desired. presenting problems or before showing the menu. Attempting to divide by zero. P0 Error 1. Press › or œ. In ‹ Man (manual) mode, you compose y

Inhaltszusammenfassung zur Seite Nr. 3

TI Product Service and Warranty Information ­ T U V W ® ! " # $ X Y (continued) ­ 3V4T2® ­ 3 3Q4+2= 14 Product Service Customers in the U.S. and Canada Only T X Y 2T3® 3VX4T2Y®Q Always contact Texas Instruments Customer Support before 2+3= 5 3Q(4+2)= 18 returning a product for service. Customers outside the U.S. and Canada U 7U4® Refer to the leaflet enclosed with this product or contact your local 7N4= 3 £ Texas Instruments retailer/distributor. £ 9£4® Other TI Products and Services 9P4= 2 r 1

Inhaltszusammenfassung zur Seite Nr. 4

¨ ¨ › œ ‹ Op1 ‹ Auto ¬ ¬25Y® › ›T5› ‹ ‹ ‡(25)= 5 +5 8+3=? 3 ¨ 5¨2® ‹ Auto Op1 11® 2› 5^2= 25 2+5 8+3=11 Yes 1 7 8¨13® Op1 ‹ Auto › 8^13= 7+5 3+?=8 5.498Q10^11 3 2 12 ‹ Auto Op1 › 5® © 3+5=8 12+5 Yes © 3 17 ©V3® pQ3= 3p Op1 Op2 ‹ Auto œ œV2œ 9+7=? Q2 3 ©V4¨2® pQ4^2= 16p ‹ Auto Op1 Op2 15® 3œ 9+7>15 3Q2 No 1 6 2T3V©® 2+3Qp= ‹ Auto Op1 Op2 18® œ 11.42477796 9+7<18 6Q2 No 2 12 z | Op1 Op2 › ‹ Auto 17® 12+5 9+7<17 96T85® 1 17 No 96+85= 181 ‹ Auto Op1 ‡$$"® Clear Op 9+7=16 M z W2®z® OP 1 OP 2 181P

Inhaltszusammenfassung zur Seite Nr. 5

‹ ‡ ‹ ‡ Œ ˜ ™ š “ ’ ‹ Auto ‘  1 2 3 ‹‡$"® 1 2 3 ‹ ‹‡ ‹‡"® _ | ~ Auto Man ‹ Auto ‡ 6+400=? ‹ ‡ 3 3 ‹ Auto 406® 6+400=406 ‹ƒ ƒ 4379r652Œ Yes 4379.652 3 ‹ Auto ‡$$""® + - Q P ? + N Q P ? ‹ƒ 3 4379.652 3.  ‹ Auto ‡ 10Q40=? ‹ƒ 3 4379.652 3"100 ‹ Auto 400® 10Q40=400 ‹ƒ 5 4379.652 Yes  . 5 ‹ Auto ‡$$!®‡ ‹ƒ 70N40=? 4379.652 3 5"0.01 ‹ Auto 20® 70N40>20 ‹ ”7653r498Œ 7653.498 No 3 ‹ Auto 30® ‹ƒ 70N40=30  7653.498 Yes 7.  ‹ƒ ‹ ‡  Ž ™ 7653.498 ‹ ‹‡ ‹‡